Quick summary
Genetics is the study of heredity and variation. Gregor Johann Mendel discovered the basic laws of inheritance by working on the garden pea. This topic covers Mendel's experiments, monohybrid and dihybrid crosses, his laws, test cross and back cross, and deviations from Mendelian ratios such as incomplete dominance, codominance, epistasis and multiple alleles.
Key points
- Gregor Johann Mendel (1822–1884), the "father of genetics", worked on the garden pea Pisum sativum (1856–1863) and published his results in 1865/1866.
- His work was rediscovered in 1900 by Hugo de Vries, Carl Correns and Erich von Tschermak.
- The term genetics was coined by William Bateson (1905); the word gene by W. Johannsen (1909).
- Mendel studied seven pairs of contrasting characters, e.g. tall/dwarf stem, round/wrinkled seed, yellow/green seed, violet/white flower.
- Reasons for success: pea is self-pollinating, has clear contrasting characters, short life cycle; he used pure lines, studied one character at a time and used statistics.
- Monohybrid cross (tall × dwarf): F₁ all tall; F₂ phenotypic ratio 3 : 1, genotypic ratio 1 : 2 : 1.
- Dihybrid cross (round yellow × wrinkled green): F₂ phenotypic ratio 9 : 3 : 3 : 1.
- Law of dominance: in a heterozygote, one factor (dominant) expresses itself and the other (recessive) does not.
- Law of segregation (purity of gametes): the two factors of a pair separate during gamete formation; each gamete gets only one.
- Law of independent assortment: factors of different characters are distributed to gametes independently of each other.
Important terms
- Allele – alternative forms of a gene (e.g. T and t).
- Homozygous / heterozygous – having identical (TT, tt) / different (Tt) alleles.
- Genotype / phenotype – genetic make-up / visible character.
- Test cross – cross of F₁ with the homozygous recessive parent; monohybrid test cross ratio 1 : 1, dihybrid 1 : 1 : 1 : 1.
- Back cross – cross of F₁ with either parent.
- Incomplete dominance – F₁ shows an intermediate character; e.g. Mirabilis jalapa (4 o'clock plant) red × white → pink; F₂ ratio 1 : 2 : 1 (both phenotypic and genotypic).
- Codominance – both alleles fully expressed in the heterozygote; e.g. AB blood group, roan coat in cattle.
- Epistasis – one gene masks the effect of another non-allelic gene.
- Multiple alleles – more than two alleles of one gene in a population; e.g. Iᴬ, Iᴮ, i of ABO blood groups.
Formulas
- Number of gamete types = 2ⁿ (n = number of heterozygous gene pairs).
- Number of F₂ genotypes = 3ⁿ; F₂ phenotypes (complete dominance) = 2ⁿ; F₂ combinations in Punnett square = 4ⁿ.
- Example: for a dihybrid (n = 2): gametes 4, genotypes 9, phenotypes 4, combinations 16.
| Interaction | F₂ ratio | Example |
|---|---|---|
| Complementary genes | 9 : 7 | Flower colour in sweet pea (Lathyrus odoratus) |
| Supplementary genes | 9 : 3 : 4 | Coat colour in mice |
| Dominant epistasis | 12 : 3 : 1 | Fruit colour in summer squash |
| Inhibitory genes | 13 : 3 | Feather colour in fowl |
| Duplicate genes | 15 : 1 | Capsule shape in Capsella |
5 important questions
Q1. State the law of segregation.
The two alleles of a gene, which stay together in an individual, separate during gamete formation. Each gamete receives only one allele, so gametes are always pure.
Q2. What is a test cross? Give its significance.
A test cross is the cross between an individual of dominant phenotype and its homozygous recessive. A 1 : 1 result shows the individual is heterozygous; all dominant offspring show it is homozygous.
Q3. Explain a dihybrid cross with a Punnett square.
- Parents: RRYY (round yellow) × rryy (wrinkled green).
- F₁: RrYy – all round yellow.
- F₁ gametes: RY, Ry, rY, ry.
- F₂ (16 boxes): 9 round yellow : 3 round green : 3 wrinkled yellow : 1 wrinkled green.
- Proves law of independent assortment.
Q4. Explain incomplete dominance with an example.
- Neither allele is fully dominant.
- Mirabilis jalapa: RR (red) × rr (white) → Rr (pink).
- F₂: 1 red : 2 pink : 1 white.
- Phenotypic and genotypic ratios are the same.
- Shows that factors do not blend; they separate again in F₂.
Q5. Explain complementary gene interaction (9 : 7).
- Two dominant genes needed together to produce a character.
- Bateson and Punnett: two white-flowered sweet pea varieties (CCpp × ccPP) gave purple F₁ (CcPp).
- F₂: 9 purple (C_P_) : 7 white (C_pp, ccP_, ccpp).
- Reason: one gene makes a precursor, the other converts it into pigment.
Exam tip
Always draw Punnett squares neatly and write both phenotypic and genotypic ratios. Memorise the gene-interaction ratio table.