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BSc First Year (Sem 1 & 2) Mathematics – Daily Revision MCQ (English Medium)

📅 28 October 2026 · 10 questions · based on the Maharashtra university syllabus

Timed quiz: 15 seconds per question, the next one loads by itself when time runs out. Or solve without the timer: tap an option, right turns green, wrong turns red. New sets are added regularly.

  1. For every real x, cosh²x − sinh²x equals:

    Chapter 6: Hyperbolic Functions and Logarithm of Complex Numbers

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    Answer: B. 1
    With cosh x = (eˣ + e⁻ˣ)/2 and sinh x = (eˣ − e⁻ˣ)/2, the difference of squares is (4eˣe⁻ˣ)/4 = 1.

  2. The nth derivative of y = e^(3x) is:

    Chapter 7: Successive Differentiation

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    Answer: D. 3ⁿe^(3x)
    Each differentiation of e^(3x) brings down a factor 3, so after n steps yₙ = 3ⁿe^(3x).

  3. For f(x) = x² − 4x + 3 on [1, 3], the value of c given by Rolle's theorem is:

    Chapter 8: Mean Value Theorems

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    Answer: C. 2
    f(1) = f(3) = 0 and f′(c) = 2c − 4 = 0 gives c = 2, which lies in (1, 3).

  4. The coefficient of x³ in the Maclaurin series of sin x is:

    Chapter 9: Taylor's and Maclaurin's Series

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    Answer: B. −1/6
    sin x = x − x³/3! + x⁵/5! − …, so the x³ coefficient is −1/3! = −1/6.

  5. At a stationary point of f(x, y), with r = fxx, s = fxy, t = fyy, if rt − s² > 0 and r < 0, the point is a:

    Chapter 12: Maxima and Minima of Two Variables and Lagrange's Multipliers

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    Answer: A. maximum
    rt − s² > 0 means an extremum; r < 0 makes it a maximum (r > 0 would give a minimum).

  6. Using the reduction formula, the value of ∫₀^(π/2) sin⁴x dx is:

    Chapter 13: Reduction Formulae

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    Answer: C. 3π/16
    ∫₀^(π/2) sin⁴x dx = (3/4)(1/2)(π/2) = 3π/16.

  7. The value of the double integral ∫₀¹ ∫₀² (x + y) dy dx is:

    Chapter 15: Double and Triple Integrals

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    Answer: D. 3
    Inner integral: [xy + y²/2] from 0 to 2 = 2x + 2; then ∫₀¹ (2x + 2) dx = 1 + 2 = 3.

  8. The general solution of Clairaut's equation y = px + p², where p = dy/dx, is:

    Chapter 17: First Order Higher Degree Equations and Clairaut's Form

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    Answer: A. y = cx + c²
    For Clairaut's form y = px + f(p), the general solution is obtained by replacing p with a constant c: y = cx + c².

  9. If a = 2i, b = 3j and c = i + j + 4k, the scalar triple product [a b c] equals:

    Chapter 18: Scalar and Vector Triple Products

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    Answer: B. 24
    b × c = 12i − 3k, so a · (b × c) = 2 × 12 = 24 (the determinant of the components also gives 24).

  10. Which theorem equates the surface integral of F · n over a closed surface S to the volume integral of div F over the region enclosed by S?

    Chapter 20: Vector Integration

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    Answer: C. Gauss divergence theorem
    Gauss's divergence theorem: ∬ F · n dS over a closed surface = ∭ div F dV over the enclosed volume.

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All questions are written by PadhaiNotes in our own words from the common syllabus of Maharashtra universities (NEP). Your own university's syllabus may differ a little.